\(x + y = \sqrt{3} + \frac{1}{\sqrt{3}} + \sqrt{3} - \frac{1}{\sqrt{3}} = 2\sqrt{3}\) \(xy = \left(\sqrt{3} + \frac{1}{\sqrt{3}}\right)\left(\sqrt{3} - \frac{1}{\sqrt{3}}\right)\) \(= (\sqrt{3})^2 - \left(\frac{1}{\sqrt{3}}\right)^2 = 3 - \frac{1}{3}\) \(= \frac{9 - 1}{3} = \frac{8}{3}\) \(\frac{x^2}{y} + \frac{y^2}{x}\) \(= \frac{x^3 + y^3}{xy}\) \(= \frac{(x + y)^3 - 3xy(x + y)}{xy}\) \(= \frac{(2\sqrt{3})^3 - 3 \times \frac{8}{3} \times 2\sqrt{3}}{\frac{8}{3}}\) \(= \frac{24\sqrt{3} - 16\sqrt{3}}{\frac{8}{3}}\) \(= 8\sqrt{3} \times \frac{3}{8}\) \(= 3\sqrt{3}\) (Answer)