Q.If one angle of a parallelogram is 67°30′, find the radian measures of the other three angles.

\(67°30' = 67 + \frac{30°}{60} = 67 + \frac{1°}{2} = \frac{135°}{2}\) \(\therefore\) The adjacent angle of the parallelogram = \(180° - \frac{135°}{2}\) \(= \frac{360° - 135°}{2} = \frac{225°}{2}\) We know that \(180° = \pi\) radians \(\therefore 1° = \frac{\pi}{180}\) radians So, \(\frac{135°}{2} = \frac{\pi}{180} \times \frac{135}{2} = \frac{9\pi}{24}\) radians And, \(\frac{225°}{2} = \frac{\pi}{180} \times \frac{225}{2} = \frac{5\pi}{8}\) radians \(\therefore\) The radian measures of the other three angles are: \(\frac{5\pi}{8}, \frac{9\pi}{24}, \frac{5\pi}{8}\) radians.
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