Answer: A
Sum of the two acute angles in a right-angled triangle = \( \frac{\pi}{2} \) radians Now, the ratio of the two acute angles is 2 : 3 = \( \frac{2}{5} : \frac{3}{5} \) Therefore, the measures of the angles are: \[ \frac{\pi}{2} \times \frac{2}{5},\quad \frac{\pi}{2} \times \frac{3}{5} = \frac{\pi}{5},\quad \frac{3\pi}{10} \]
Sum of the two acute angles in a right-angled triangle = \( \frac{\pi}{2} \) radians Now, the ratio of the two acute angles is 2 : 3 = \( \frac{2}{5} : \frac{3}{5} \) Therefore, the measures of the angles are: \[ \frac{\pi}{2} \times \frac{2}{5},\quad \frac{\pi}{2} \times \frac{3}{5} = \frac{\pi}{5},\quad \frac{3\pi}{10} \]