Q.In triangle ABC, \(\angle\)BAC = 90°, and AD is perpendicular to BC. Given: AC = 8 cm, AB = 6 cm Find: The length of BD. (a) 6 cm (b) 1.5 cm (c) 3 cm (d) 3.6 cm
Answer: D
In right-angled triangle ABC: \(BC = \sqrt{AB^2 + AC^2} = \sqrt{6^2 + 8^2} = 10\) cm Also, triangles ABC and ABD are similar. ∴ \(\cfrac{AB}{BC} = \cfrac{BD}{AB}\) i.e., \(BC \times BD = AB^2\) ⇒ \(10 \times BD = 6^2\) ⇒ \(BD = \cfrac{36}{10} = 3.6\)
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