Q.If the difference between the measures of the two acute angles in a right-angled triangle is 10°, determine their circular measures.

Let the larger acute angle be \(x\).
\(\therefore\) The other acute angle is \((x - 10°)\).
According to the given condition, \(x + x - 10° = 90°\).
Or, \(2x = 90° + 10°\).
Or, \(x = \cfrac{100°}{2} = 50°\).
Thus, one angle is \(50° = \cfrac{50 \times \pi}{180}\) radians \(= \cfrac{5\pi}{18}\) radians.
And the other angle is \(90° - 50° = 40°\) \(= \cfrac{40 \times \pi}{180}\) radians \(= \cfrac{2\pi}{9}\) radians.

\(\therefore\) The circular measures of the two angles are \(\cfrac{5\pi}{18}\) radians and \(\cfrac{2\pi}{9}\) radians.
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