Given: \(\frac{2}{3}\) of A = 75% of B = 0.6 of C \[ \frac{2A}{3} = \frac{75B}{100} = \frac{6C}{10} \] Let \(\frac{2A}{3} = \frac{75B}{100} = \frac{6C}{10} = k\) Then: \[ A = \frac{3k}{2}, \quad B = \frac{100k}{75}, \quad C = \frac{10k}{6} \] So, \[ A : B : C = \frac{3k}{2} : \frac{100k}{75} : \frac{10k}{6} \] Removing the common factor \(k\): \[ = \frac{3}{2} : \frac{4}{3} : \frac{5}{3} \] To simplify, multiply all terms by 6 (LCM of denominators): \[ = \frac{9}{6} : \frac{8}{6} : \frac{10}{6} = 9 : 8 : 10 \]