Q.If ABCD is a cyclic quadrilateral and \(\angle\)A=120°, what is the measure of \(\angle\)C ? (a) \(\cfrac{π}{3}\) (b) \(\cfrac{π}{6}\) (c) \(\cfrac{π}{2}\) (d) \(\cfrac{2π}{3}\)
Answer: A
\(\angle\)C=180°-\(\angle\)A
=180°-120°=60°
=60×\(\cfrac{\pi}{180}\)=\(\cfrac{\pi}{3}\)
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