Q.AB is the diameter of a circle, and PQ is a chord that stands perpendicular to AB at point O. Given: OA = 8 cm, OB = 2 cm, OP = 4 cm Find: The length of OQ. (a) 6 cm (b) 4 cm (c) 5 cm (d) None of the above
Answer: B
In triangles AOP and QOB: \(\angle\)AOP = \(\angle\)QOB [both are right angles] \(\angle\)OAP = \(\angle\)OPB [both are angles subtended by arc PB] ∴ Triangles AOP and QOB are similar. ∴ \(\cfrac{OP}{OB} = \cfrac{OA}{OQ}\) i.e., \(\cfrac{4}{2} = \cfrac{8}{OQ}\) ⇒ \(OQ = 4\) So, OQ = 4 cm.
Similar Questions