Q.If \(\sec^2 \theta + \tan^2 \theta = \frac{13}{12}\), then what is the value of \(\sec^4 \theta - \tan^4 \theta\)?

\[ \sec^4 \theta - \tan^4 \theta = (\sec^2 \theta)^2 - (\tan^2 \theta)^2 = (\sec^2 \theta + \tan^2 \theta)(\sec^2 \theta - \tan^2 \theta) = \frac{13}{12} \times 1 = \frac{13}{12} \quad \text{(Answer)} \]
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