Q.In triangle ABC, ∠A = 90°, AB = 12 cm, AC = 5 cm, and BC = 13 cm. A perpendicular AD is drawn from point A to side BC. What is the length of AD?

Area of the triangle: \(\frac{1}{2} \times AC \times AB = \frac{1}{2} \times BC \times AD\) ⇒ \(AC \times AB = BC \times AD\) ⇒ \(5 \times 12 = 13 \times AD\) ⇒ \(AD = \frac{60}{13}\) ∴ The length of AD is \(\frac{60}{13}\) cm.
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