Q.In triangle ABC, ∠A = 90°, AB = 12 cm, AC = 5 cm, and BC = 13 cm. A perpendicular AD is drawn from point A to side BC. What is the length of AD?
Area of the triangle:
\(\frac{1}{2} \times AC \times AB = \frac{1}{2} \times BC \times AD\)
⇒ \(AC \times AB = BC \times AD\)
⇒ \(5 \times 12 = 13 \times AD\)
⇒ \(AD = \frac{60}{13}\)
∴ The length of AD is \(\frac{60}{13}\) cm.