Assume Mr. Gobinda deposited ₹\(x\) in the bank and the remaining ₹\((500000 - x)\) in the post office. Bank Details Principal \(p = x\), Time \(t = 1\) year, Interest rate \(r = 6\%\) Simple interest from bank = \(\frac{ptr}{100} = \frac{6x}{100}\) **Post Office Details** Principal \(p = 500000 - x\), Time \(t = 1\) year, Interest rate \(r = 7.2\%\) Simple interest from post office = \(\frac{7.2(500000 - x)}{100}\) **Given:** Total annual interest = ₹33600 So, \[ \frac{6x}{100} + \frac{7.2(500000 - x)}{100} = 33600 \] Multiply both sides by 100: \[ 6x + 3600000 - 7.2x = 3360000 \] \[ -1.2x + 3600000 = 3360000 \] \[ 1.2x = 240000 \Rightarrow x = \frac{240000 \times 10}{12} = ₹200000 \] - Bank deposit = ₹200000 - Post office deposit = ₹300000