Q.The value of (sin43°cos47° +cos43°sin47°) is: (a) 0 (b) 1 (c) sin4° (d) cos4°
Answer: B
sin43°cos47°+cos43°sin47°
=sin43°.cos⁡(90°-43°)+cos43°.sin⁡(90°-43°)
= sin43°.sin43°+cos43°.cos43°
=sin\(^2\)43°+cos\(^2\)43°
=1
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