Answer: B
Time \((t) = \cfrac{1}{365}\) years
Interest rate \((r) = 10\%\)
Interest \((I) = 1\) rupee
∴ Principal \((p) = \cfrac{100 \times I}{t \times r}\)
\[ = \cfrac{100 \times 1}{\cfrac{1}{365} \times 10} = \cfrac{365 \times 100}{10}\, \text{rupees} \]
\(= 3650\) rupees.
Time \((t) = \cfrac{1}{365}\) years
Interest rate \((r) = 10\%\)
Interest \((I) = 1\) rupee
∴ Principal \((p) = \cfrac{100 \times I}{t \times r}\)
\[ = \cfrac{100 \times 1}{\cfrac{1}{365} \times 10} = \cfrac{365 \times 100}{10}\, \text{rupees} \]
\(= 3650\) rupees.