Let \(\frac{a}{b} = \frac{b}{c} = k\) ∴ \(a = bk = ck^2\), and \(b = ck\) Left-hand side = \(abc(a + b + c)^3\) = \(ck^2 \cdot ck \cdot c \cdot (ck^2 + ck + c)^3\) = \(c^3k^3 \cdot \{c(k^2 + k + 1)\}^3\) = \(c^3k^3 \cdot c^3(k^2 + k + 1)^3\) = \(c^6k^3(k^2 + k + 1)^3\) Right-hand side = \((ab + bc + ca)^3\) = \((ck^2 \cdot ck + ck \cdot c + c \cdot ck^2)^3\) = \(\{c^2k(k^2 + 1 + k)\}^3\) = \(c^6k^3(k^2 + k + 1)^3\) ∴ Left-hand side = Right-hand side (Proved)