Q.A hollow sphere made of lead sheet with a thickness of 1 cm has an outer radius of 6 cm. After melting the sphere, a solid cylindrical rod with a radius of 2 cm is formed. What is the length of the rod?

The inner radius of the sphere = (6 − 1) cm = 5 cm ∴ Volume of the hollow sphere = \( \frac{4}{3} \pi (6^3 - 5^3) \) cubic cm \( = \frac{4}{3} \pi (216 - 125) \) cubic cm \( = \frac{4}{3} \pi \times 91 \) cubic cm Let the length of the rod be \( h \) cm ∴ \( \pi (2)^2 \times h = \frac{4}{3} \pi \times 91 \) i.e., \( h = \frac{91}{3} = 30\frac{1}{3} \) ∴ The length of the rod will be \( 30\frac{1}{3} \) cm.
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