Let the number of villagers be \(N\) and the number of days be \(D\). Since the total amount of work remains constant, increasing (or decreasing) the number of villagers will decrease (or increase) the number of days. Therefore, \(N\) and \(D\) are inversely proportional. So, \(N ∝ \frac{1}{D}\) ∴ \(N = \frac{k}{D}\), where \(k\) is a non-zero constant. Given: \(N = 50\) when \(D = 18\) So, \(50 = \frac{k}{18}\) ⇒ \(k = 900\) ∴ \(N = \frac{900}{D}\) ———(i) Now, substituting \(D = 15\) in equation (i): \(N = \frac{900}{15} = 60\) ∴ Additional people required = \(60 - 50 = 10\) people.