Answer: A
\((\sqrt[3]{2})^{12} = 2^4 = 16\) \((\sqrt[4]{3})^{12} = 3^3 = 27\) \((\sqrt[6]{5})^{12} = 5^2 = 25\) Here, \( 16 < 25 < 27 \) Therefore, \( \sqrt[3]{2} < \sqrt[6]{5} < \sqrt[4]{3} \) So, the smallest number is \( \sqrt[3]{2} \)
\((\sqrt[3]{2})^{12} = 2^4 = 16\) \((\sqrt[4]{3})^{12} = 3^3 = 27\) \((\sqrt[6]{5})^{12} = 5^2 = 25\) Here, \( 16 < 25 < 27 \) Therefore, \( \sqrt[3]{2} < \sqrt[6]{5} < \sqrt[4]{3} \) So, the smallest number is \( \sqrt[3]{2} \)