Q.In triangle ∆ABO, the circumcenter is C; If \(\angle\)CAB=50° then what is \(\angle\)AOB =? (a) 50° (b) 100° (c) 40° (d) 80°
Answer: C
Points B and C are joined
In Triangle ∆ABC,
AC=BC (the radius of the circle)
Therefore, ∠ABC=∠CAB=50°
∴∠ACB=180°-(50°+50°) =80°

The central angle ∠AOB is half of the inscribed angle ∠ACB
So, ∠AOB=\(\cfrac{1}{2}\angle\)ACB=\(\cfrac{80°}{2}\)=40°
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