Answer: C
Points B and C are joined
In Triangle ∆ABC,
AC=BC (the radius of the circle)
Therefore, ∠ABC=∠CAB=50°
∴∠ACB=180°-(50°+50°) =80°
The central angle ∠AOB is half of the inscribed angle ∠ACB
So, ∠AOB=\(\cfrac{1}{2}\angle\)ACB=\(\cfrac{80°}{2}\)=40°
Points B and C are joined
In Triangle ∆ABC,
AC=BC (the radius of the circle)
Therefore, ∠ABC=∠CAB=50°
∴∠ACB=180°-(50°+50°) =80°
The central angle ∠AOB is half of the inscribed angle ∠ACB
So, ∠AOB=\(\cfrac{1}{2}\angle\)ACB=\(\cfrac{80°}{2}\)=40°