Q.The roots of the equation \(ax^2+bx+c=0\) will be equal in magnitude but opposite in sign if- (a) \(c=0, a≠0\) (b) \(b=0, a≠0\) (c) \(c=0, a=0\) (d) \(b=0, a=0\)
Answer: B
If one root of the equation is \(α\) , the other root will be \(-α\)
Then, the equation becomes:
\(x^2-(α-α)x+(α×-α)=0\)
Or, \(x^2-0.x-α^2=0\)

∓ Comparing with \(ax^2+bx+c=0\), we get: \(a≠0,b=0,c≠0\)
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