Q.If \( \tanθ + \cotθ = 2 \), the value of \( \tanθ - \cotθ \) will be (a) 2 (b) 0 (c) -2 (d) \(\cfrac{1}{2}\)
Answer: B
\((tanθ-cotθ)^2\)
\(=(tanθ+cotθ)^2-4tanθ.cotθ\)
\(=(2)^2-4.tanθ.\cfrac{1}{tanθ}\)
\(=4-4=0\)
∴tanθ-cotθ=0
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