Answer: A
We know, Volume of a cone = \(\frac{1}{3} \times\) base area \(\times\) height i.e., \(V = \frac{1}{3}AH\) i.e., \(AH = 3V\) i.e., \(H = \frac{3V}{A}\)
We know, Volume of a cone = \(\frac{1}{3} \times\) base area \(\times\) height i.e., \(V = \frac{1}{3}AH\) i.e., \(AH = 3V\) i.e., \(H = \frac{3V}{A}\)