Q.In triangle ∆ABC, a straight line parallel to side BC intersects sides AB and AC at points P and Q respectively. Given that PB = AQ, AP = 9 units, and QC = 16 units, what is the length of PB? (a) 12 cm (b) 6 cm (c) 8 cm (d) 10 cm
Answer: A
In triangle ∆ABC, PQ is parallel to BC. ∴ \(\frac{AP}{PB} = \frac{AQ}{QC}\) ∴ \(\frac{AP}{PB} = \frac{PB}{QC}\) [because PB = AQ] Therefore, \(PB^2 = AP \times QC\) ⇒ \(PB^2 = 9 \times 16\) ⇒ \(PB = \sqrt{144} = 12\) ∴ PB = 12 cm
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