Q.AB is a diameter of a circle with center O, and P is a point on the circle. If ∠POA = 120°, then the measure of ∠PBO is — (a) 30° (b) 45° (c) 60° (d) 90°
Answer: C
\(\angle\)POA = 120° ∴ In triangle BOP, \(\angle\)PBO + \(\angle\)BPO = exterior angle \(\angle\)POA i.e., 2\(\angle\)PBO = 120° [∵ OB = OP = radius of the circle ∴ \(\angle\)PBO = \(\angle\)BPO] Therefore, \(\angle\)PBO = 60°
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