Q.Solve: \(x^2 + 7x + 6 = 0\) (a) x = 6, 1 (b) x = -1,-6 (c) x = 6, 6 (d) x = 1, 3
Answer: B
\(x^2 + 7x + 6 = 0\)
Or, \(x^2 + (6 + 1)x + 6 = 0\)
Or, \(x^2 + 6x + x + 6 = 0\)
Or, \(x(x + 6) + (x + 6) = 0\)
Or, \((x + 6)(x + 1) = 0\)

\(\therefore\) Either, \((x + 6) = 0\)
Or, \(x = -6\)

Or, \((x + 1) = 0\)
Or, \(x = -1\)

The roots of the equation \(x^2 + 7x + 6 = 0\) are \(-6, -1\).
Similar Questions