Answer: B
Let the radius of the sphere be \(r\) cm. \(\therefore 3\pi r^2 = 462\) i.e., \(3 \times \frac{22}{7} \times r^2 = 462\) So, \(r^2 = 462 \times \frac{7}{22 \times 3}\) i.e., \(r^2 = 7 \times 7\) So, \(r = 7\) \(\therefore\) The diameter of the sphere \(= 7 \times 2\) cm = \(14\) cm.
Let the radius of the sphere be \(r\) cm. \(\therefore 3\pi r^2 = 462\) i.e., \(3 \times \frac{22}{7} \times r^2 = 462\) So, \(r^2 = 462 \times \frac{7}{22 \times 3}\) i.e., \(r^2 = 7 \times 7\) So, \(r = 7\) \(\therefore\) The diameter of the sphere \(= 7 \times 2\) cm = \(14\) cm.