If \(3x = 4y = 5z\), then \(x : y : z = 20 : 15 : 12\).
Let \(3x = 4y = 5z = k\) \(\therefore x = \cfrac{k}{3},\ y = \cfrac{k}{4},\ z = \cfrac{k}{5}\) \(\therefore x : y : z = \cfrac{k}{3} : \cfrac{k}{4} : \cfrac{k}{5}\) \(= \cfrac{1}{3} : \cfrac{1}{4} : \cfrac{1}{5}\) \(= \cfrac{60}{3} : \cfrac{60}{4} : \cfrac{60}{5}\) \(= 20 : 15 : 12\)