Q.In triangle \( \triangle ABC \), a straight line parallel to side BC intersects sides AB and AC at points P and Q respectively. Given that \( AP = 18 \) cm, \( QC = 9 \) cm, and \( AQ = 2 \times PB \), find the length of \( PB \). (a) 6 cm (b) 12 cm (c) 18 cm (d) 9 cm
Answer: D
In triangle \( \triangle ABC \), PQ is parallel to BC ∴ \( \frac{AP}{PB} = \frac{AQ}{QC} \) ∴ \( \frac{AP}{PB} = \frac{2PB}{QC} \) [because \( AQ = 2PB \)] i.e., \( 2PB^2 = AP \times QC \) ⇒ \( 2PB^2 = 18 \times 9 \) ⇒ \( PB^2 = 81 \) ∴ \( PB = \sqrt{81} = 9 \) ∴ \( PB = 9 \) cm
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