A and B are joined, intersecting OP at point M. In the right-angled triangle \( \triangle BMP \): \( BM^2 = BP^2 - MP^2 = 10^2 - \left(\frac{16}{2}\right)^2 = 100 - 64 = 36 \) \(\therefore BA and B are joined, intersecting OP at point M. In the right-angled triangle \( \triangle BMP \): \( BM^2 = BP^2 - MP^2 = 10^2 - \left(\frac{16}{2}\right)^2 = 100 - 64 = 36 \) \(\therefore BM = \sqrt{36} = 6\) cm \(\therefore\) Area of triangle \( \triangle POB = \frac{1}{2} \times \text{OP} \times \text{BM} \) \(= \frac{1}{2} \times 16 \times 6\) square cm \(= 48\) square cm.M = \sqrt{36} = 6\) cm \(\therefore\) Area of triangle \( \triangle POB = \frac{1}{2} \times \text{OP} \times \text{BM} \) \(= \frac{1}{2} \times 16 \times 6\) square cm \(= 48\) square cm.