Q.In triangle ABC, a straight line parallel to side BC intersects AB at point P and AC at point Q. If AP = 4 cm, QC = 9 cm, and PB = AQ, then find the length of PB.

AP = 4 cm, QC = 9 cm, and PB = AQ In this case, \(\cfrac{AP}{PB} = \cfrac{AQ}{QC}\) So, \(\cfrac{4}{PB} = \cfrac{PB}{9}\) Therefore, \(PB^2 = 36\) So, \(PB = 6\) \(\therefore\) The length of PB is 6 cm.
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