In triangle ABC, AB = (2a − 1) cm, AC = 2√2a cm, and BC = (2a + 1) cm. Find the measure of ∠BAC.

Q.In triangle ABC, AB = (2a − 1) cm, AC = 2√2a cm, and BC = (2a + 1) cm. Find the measure of ∠BAC.

Here, AB² + AC² = (2a − 1)² + (2√2a)² = 4a² − 4a + 1 + 8a = 4a² + 4a + 1 = (2a + 1)² = BC² ∴ ∆ABC is a right-angled triangle with BC as the hypotenuse. ∴ ∠BAC = 90°