Answer: C
If a line is drawn through point D parallel to BF, it intersects AC at point G. In triangle \( \triangle ADG \), EF is parallel to DG. ∴ \( AF : FG = AE : ED = 1 : 2 \) Again, in triangle \( \triangle FBC \), BF is parallel to DG. ∴ \( FG : GC = BD : DC = 1 : 1 \) (because AD is a median) ∴ \( AF : FG : GC = 1 : 2 : 2 \) ∴ \( AF = \frac{1}{5} \times AC = 2 \) cm
If a line is drawn through point D parallel to BF, it intersects AC at point G. In triangle \( \triangle ADG \), EF is parallel to DG. ∴ \( AF : FG = AE : ED = 1 : 2 \) Again, in triangle \( \triangle FBC \), BF is parallel to DG. ∴ \( FG : GC = BD : DC = 1 : 1 \) (because AD is a median) ∴ \( AF : FG : GC = 1 : 2 : 2 \) ∴ \( AF = \frac{1}{5} \times AC = 2 \) cm