Answer: B
sinθ + cosθ = √2 --- (i)
Or, \((sinθ + cosθ)^2 = 2\)
Or, \(sin^2θ + cos^2θ + 2sinθcosθ = 2\)
Or, \(1 + 2sinθcosθ = 2\)
Or, \(2sinθcosθ = 1\)
Or, \(1 - 2sinθcosθ = 0\)
Or, \(sin^2θ + cos^2θ - 2sinθcosθ = 0\)
Or, \((sinθ - cosθ)^2 = 0\)
Or, \(sinθ - cosθ = 0\) --- (ii)
Adding (i) and (ii), we get \(2sinθ = √2\)
Or, \(sinθ = \cfrac{1}{√2} = sin45°\)
Thus, \(θ = 45°\).
sinθ + cosθ = √2 --- (i)
Or, \((sinθ + cosθ)^2 = 2\)
Or, \(sin^2θ + cos^2θ + 2sinθcosθ = 2\)
Or, \(1 + 2sinθcosθ = 2\)
Or, \(2sinθcosθ = 1\)
Or, \(1 - 2sinθcosθ = 0\)
Or, \(sin^2θ + cos^2θ - 2sinθcosθ = 0\)
Or, \((sinθ - cosθ)^2 = 0\)
Or, \(sinθ - cosθ = 0\) --- (ii)
Adding (i) and (ii), we get \(2sinθ = √2\)
Or, \(sinθ = \cfrac{1}{√2} = sin45°\)
Thus, \(θ = 45°\).