Q.If \(x \propto y\) and \(y \propto z\), then show that \[ \frac{x}{yz} + \frac{y}{zx} + \frac{z}{xy} \propto \frac{1}{x} + \frac{1}{y} + \frac{1}{z} \]

Given: \[ x \propto y \Rightarrow x = ky \quad \text{[where \(k\) is a non-zero constant]} \] Again, \[ y \propto z \Rightarrow z \propto y \Rightarrow z = my \quad \text{[where \(m\) is a non-zero constant]} \] Now, \[ \frac{\frac{x}{yz} + \frac{y}{zx} + \frac{z}{xy}}{\frac{1}{x} + \frac{1}{y} + \frac{1}{z}} = \frac{\frac{x^2 + y^2 + z^2}{xyz}}{\frac{yz + zx + xy}{xyz}} = \frac{x^2 + y^2 + z^2}{xy + yz + zx} \] Substituting \(x = ky\) and \(z = my\): \[ = \frac{k^2y^2 + y^2 + m^2y^2}{ky \cdot y + y \cdot my + my \cdot ky} = \frac{y^2(k^2 + 1 + m^2)}{y^2(k + m + mk)} = \frac{k^2 + m^2 + 1}{mk + k + m} = \text{constant} \] \[ \therefore\ \frac{x}{yz} + \frac{y}{zx} + \frac{z}{xy} \propto \frac{1}{x} + \frac{1}{y} + \frac{1}{z} \quad \text{[Proved]} \]
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