Q.The radius of a circle is 13 cm and the length of a chord is 10 cm. What is the distance from the center of the circle to the chord? (a) 12.5 cm (b) 12 cm (c) \(\sqrt{69}\) cm (d) \(\sqrt{24}\) cm
Answer: B
Let AB = 10 cm, \(\therefore\) AP = 5 cm OA = 13 cm \(\therefore\) In the right-angled triangle \(\triangle OAP\), \(OP^2 = OA^2 - AP^2\) i.e., \(OP^2 = 13^2 - 5^2 = 169 - 25 = 144\) \(\therefore\) \(OP = 12\) \(\therefore\) The distance from the center of the circle to the chord is 12 cm.
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