Answer: B
Let AB = 10 cm, \(\therefore\) AP = 5 cm OA = 13 cm \(\therefore\) In the right-angled triangle \(\triangle OAP\), \(OP^2 = OA^2 - AP^2\) i.e., \(OP^2 = 13^2 - 5^2 = 169 - 25 = 144\) \(\therefore\) \(OP = 12\) \(\therefore\) The distance from the center of the circle to the chord is 12 cm.
Let AB = 10 cm, \(\therefore\) AP = 5 cm OA = 13 cm \(\therefore\) In the right-angled triangle \(\triangle OAP\), \(OP^2 = OA^2 - AP^2\) i.e., \(OP^2 = 13^2 - 5^2 = 169 - 25 = 144\) \(\therefore\) \(OP = 12\) \(\therefore\) The distance from the center of the circle to the chord is 12 cm.