Let the volume of a sphere with radius \(r\) cm be \(v\) cubic cm. So, \(v \propto r^3\) \(\therefore v = kr^3\) [where \(k\) is a non-zero constant] Therefore, - Volume of a sphere with radius 3 cm = \(k \times 3^3 = 27k\) cubic cm - Volume of a sphere with radius 4 cm = \(k \times 4^3 = 64k\) cubic cm - Volume of a sphere with radius 5 cm = \(k \times 5^3 = 125k\) cubic cm According to the question, the volume of the new sphere = \(27k + 64k + 125k = 216k\) cubic cm If the radius of the new sphere is \(R\) cm, then \(kR^3 = 216k\) \(\Rightarrow R^3 = 216\) \(\Rightarrow R^3 = 6^3\) \(\Rightarrow R = 6\) \(\therefore\) Diameter of the new sphere = \(6 \times 2 = 12\) cm.