Q.What is the value of \(\cfrac{1}{\tan\theta+\cfrac{1}{\tan\theta}}\)? (a) \(tan\theta\) (b) \(sin 2\theta\) (c) \(cos \theta\) (d) \(sin\theta cos\theta\)
Answer: D
\(\cfrac{1}{\tan\theta+\cfrac{1}{\tan\theta}} = \cfrac{1}{\cfrac{\sin\theta}{\cos\theta}+\cfrac{\cos\theta}{\sin\theta}} = \cfrac{1}{\cfrac{\sin^2\theta+\cos^2\theta}{\sin\theta\cos\theta}} = \sin\theta\cos\theta\)
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