Let \(n\) solid spheres be formed. Now, the length of the cylindrical rod = 1 meter = 1000 mm And radius = \(\frac{4}{2}\) cm = 2 cm = 20 mm \(\therefore\) \(\frac{4}{3} \times \pi \times 5^3 \times n = \pi \times 20^2 \times 1000\) i.e., \(\frac{500\pi n}{3} = 400000\pi\) i.e., \(n = \frac{400000 \times 3}{500} = 2400\) \(\therefore\) 2400 solid spheres can be formed.