Q.If \( x ∝ y \) and \( y ∝ z \), prove that \[ x^2 + y^2 + z^2 ∝ xy + yz + zx \]

Since \( x ∝ y \), ∴ \( x = ky \) [where \( k \) is a non-zero constant] Again, since \( y ∝ z \), ∴ \( z ∝ y \) i.e., \( z = my \) [where \( m \) is a non-zero constant] Now, \[ \frac{x^2 + y^2 + z^2}{xy + yz + zx} = \frac{k^2y^2 + y^2 + m^2y^2}{ky \cdot y + y \cdot my + my \cdot ky} = \frac{y^2(k^2 + 1 + m^2)}{y^2(k + m + mk)} = \frac{k^2 + m^2 + 1}{mk + k + m} = \text{constant} \] ∴ \( x^2 + y^2 + z^2 ∝ xy + yz + zx \) [Proved]
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