Let the present value of the machine be ₹\(p\) Rate of depreciation \(r = 10\%\) Time \(n = 3\) years ∴ After 3 years, the value of the machine will be: \[ p\left(1 - \frac{r}{100}\right)^n = p\left(1 - \frac{10}{100}\right)^3 = p\left(\frac{90}{100}\right)^3 = p \times \left(\frac{9}{10}\right)^3 = p \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} \] According to the question: \[ p \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} = 43,740 \Rightarrow p = \frac{43,740 \times 10 \times 10 \times 10}{9 \times 9 \times 9} \Rightarrow p = 60,000 \] ∴ The present value of the machine is ₹60,000.