Q.What is the ratio of the surface area of a cube to the curved surface area of the largest sphere that can be inscribed within it?

The diameter of the largest sphere that can be inscribed in a cube will be equal to the length of the cube’s edge. Let each edge of the cube be \(2a\) cm. \(\therefore\) The radius of the sphere will be \(a\) cm. \(\therefore\) The ratio of the surface area of the cube to the curved surface area of the inscribed sphere is: \(= 6 \times (2a)^2 : 4\pi a^2\) \(= 6 \times 4a^2 : 4 \times \frac{22}{7} \times a^2\) \(= 6 : \frac{22}{7}\) \(= 42 : 22\) \(= 21 : 11\)
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