Q.If the sum of the roots of the equation \(x^2 - x = k(2x - 1)\) is 2, find the value of \(k\).

Given: \(x^2 - x = K(2x - 1)\) \[ \Rightarrow x^2 - x - 2Kx + K = 0 \Rightarrow x^2 - x(1 + 2K) + K = 0 \] \[ \therefore\ \alpha + \beta = (1 + 2K) \] According to the question, \((1 + 2K) = 2\) \[ \Rightarrow 2K = 2 - 1 = 1 \Rightarrow K = \cfrac{1}{2} \] \[ \therefore\ \text{The value of } K \text{ is } \cfrac{1}{2} \text{ (Answer)} \]
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