Q.In a circle with center \(O\), \(AB\) is a diameter. \(P\) is any point on the circumference. If \(\angle POA = 120°\), then the measurement of \(\angle PBO\) is – (a) 30° (b) 60° (c) 90° (d) 120°
Answer: B
\(\angle\)POA = 120°
∴ In \(\triangle BOP\), \(\angle PBO + \angle BPO =\) the exterior \(\angle POA\)
or, \(2\angle PBO = 120°\)
[∵ \(OB = OP\), as they are radii of the circle, ∴ \(\angle PBO = \angle BPO\)]
or, \(\angle PBO = 60°\).
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