Answer: B
\(\angle\)POA = 120°
∴ In \(\triangle BOP\), \(\angle PBO + \angle BPO =\) the exterior \(\angle POA\)
or, \(2\angle PBO = 120°\)
[∵ \(OB = OP\), as they are radii of the circle, ∴ \(\angle PBO = \angle BPO\)]
or, \(\angle PBO = 60°\).
\(\angle\)POA = 120°
∴ In \(\triangle BOP\), \(\angle PBO + \angle BPO =\) the exterior \(\angle POA\)
or, \(2\angle PBO = 120°\)
[∵ \(OB = OP\), as they are radii of the circle, ∴ \(\angle PBO = \angle BPO\)]
or, \(\angle PBO = 60°\).