Answer: D
If \(\alpha, \beta\) are the roots of the equation \(3x^2+8x+2=0\), then \[ \alpha+\beta=-\cfrac{8}{3} \] and \[ \alpha\beta=\cfrac{2}{3} \] \(\therefore\) \[ \cfrac{1}{\alpha}+\cfrac{1}{\beta} = \cfrac{\beta+\alpha}{\alpha\beta} \] \[ = \cfrac{-\cfrac{8}{3}}{\cfrac{2}{3}} \] \[ = -\cfrac{\cancel84}{\cancel3} \times \cfrac{\cancel3}{\cancel2} \] \[ = -4 \] (Answer)
If \(\alpha, \beta\) are the roots of the equation \(3x^2+8x+2=0\), then \[ \alpha+\beta=-\cfrac{8}{3} \] and \[ \alpha\beta=\cfrac{2}{3} \] \(\therefore\) \[ \cfrac{1}{\alpha}+\cfrac{1}{\beta} = \cfrac{\beta+\alpha}{\alpha\beta} \] \[ = \cfrac{-\cfrac{8}{3}}{\cfrac{2}{3}} \] \[ = -\cfrac{\cancel84}{\cancel3} \times \cfrac{\cancel3}{\cancel2} \] \[ = -4 \] (Answer)