Answer: B
Let the third quantity be \(x\) \(\therefore \cfrac{3}{2} = \cfrac{2}{x}\) That is, \(3x = 4\) So, \(x = \cfrac{4}{3}\) Let the fourth quantity be \(y\) \(\therefore \cfrac{2}{\cfrac{4}{3}} = \cfrac{\cfrac{4}{3}}{y}\) That is, \(2y = \cfrac{4}{3} \times \cfrac{4}{3}\) So, \(y = \cfrac{16}{9 \times 2} = \cfrac{8}{9}\)
Let the third quantity be \(x\) \(\therefore \cfrac{3}{2} = \cfrac{2}{x}\) That is, \(3x = 4\) So, \(x = \cfrac{4}{3}\) Let the fourth quantity be \(y\) \(\therefore \cfrac{2}{\cfrac{4}{3}} = \cfrac{\cfrac{4}{3}}{y}\) That is, \(2y = \cfrac{4}{3} \times \cfrac{4}{3}\) So, \(y = \cfrac{16}{9 \times 2} = \cfrac{8}{9}\)