Q.If \(a, b, c\) are in continued proportion, prove that \((a + b + c)(a - b + c) = a^2 + b^2 + c^2\).

Let \(\cfrac{a}{b} = \cfrac{b}{c} = k\) \(\therefore a = bk = ck^2,\quad b = ck\) \(\therefore\) Left-hand side = \((a + b + c)(a - b + c)\) \(= (ck^2 + ck + c)(ck^2 - ck + c)\) \(= c(k^2 + k + 1) \times c(k^2 - k + 1)\) \(= c^2[(k^2 + 1)^2 - k^2]\) \(= c^2[k^4 + 2k^2 + 1 - k^2]\) \(= c^2(k^4 + k^2 + 1)\) Right-hand side = \(a^2 + b^2 + c^2\) \(= c^2k^4 + c^2k^2 + c^2\) \(= c^2(k^4 + k^2 + 1)\) \(\therefore\) Left-hand side = Right-hand side (Proved)
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