\(\sin 10\theta = \cos 8\theta\) i.e., \(\sin 10\theta = \sin(90^\circ - 8\theta)\) \(\therefore 10\theta = 90^\circ - 8\theta\) i.e., \(18\theta = 90^\circ\) i.e., \(\theta = 5^\circ\) \(\therefore \tan 9\theta = \tan(9 \times 5^\circ) = \tan 45^\circ = 1\) (Answer)