Q.In triangle ABC, the incenter is O. If \(\angle\)BOC = 120°, then what is the measure of \(\angle\)BAC? (a) 60° (b) 90° (c) 45° (d) 120°
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In triangle OBC: \(\angle ABC + \angle ACB = 180^\circ - \angle BOC = 180^\circ - 120^\circ = 60^\circ\) Since O is the incenter of triangle ABC, Therefore, OB and OC are the angle bisectors of \(\angle ABC\) and \(\angle ACB\), respectively. So, \(\angle ABC + \angle ACB = 2(\angle OBC + \angle OCB) = 2 \times 60^\circ = 120^\circ\) Therefore, \(\angle BAC = 180^\circ - (\angle ABC + \angle ACB) = 180^\circ - 120^\circ = 60^\circ\)
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