Answer: B
\(tan\alpha + cot\alpha = 2\)
or, \(tan\alpha + \cfrac{1}{tan\alpha} = 2\)
or, \(\cfrac{tan^2\alpha + 1}{tan\alpha} = 2\)
or, \(tan^2\alpha + 1 = 2tan\alpha\)
or, \(tan^2\alpha + 1 - 2tan\alpha = 0\)
or, \((tan\alpha - 1)^2 = 0\)
or, \(tan\alpha - 1 = 0\)
or, \(tan\alpha = 1\)
\(\therefore cot\alpha = 1\)
\(\therefore tan^{13}\alpha + cot^{13}\alpha = 1^{13} + 1^{13} = 1 + 1 = 2\)
\(tan\alpha + cot\alpha = 2\)
or, \(tan\alpha + \cfrac{1}{tan\alpha} = 2\)
or, \(\cfrac{tan^2\alpha + 1}{tan\alpha} = 2\)
or, \(tan^2\alpha + 1 = 2tan\alpha\)
or, \(tan^2\alpha + 1 - 2tan\alpha = 0\)
or, \((tan\alpha - 1)^2 = 0\)
or, \(tan\alpha - 1 = 0\)
or, \(tan\alpha = 1\)
\(\therefore cot\alpha = 1\)
\(\therefore tan^{13}\alpha + cot^{13}\alpha = 1^{13} + 1^{13} = 1 + 1 = 2\)