Answer: D
Let the radii of the two right circular cones be \(2r\) units and \(3r\) units respectively, and their heights be \(3h\) units and \(2h\) units respectively. \(\therefore\) The ratio of their volumes \(= \cfrac{1}{3}\pi(2r)^2 \times 3h : \cfrac{1}{3}\pi(3r)^2 \times 2h\) \(= 12r^2h : 18r^2h\) \(= 2 : 3\)
Let the radii of the two right circular cones be \(2r\) units and \(3r\) units respectively, and their heights be \(3h\) units and \(2h\) units respectively. \(\therefore\) The ratio of their volumes \(= \cfrac{1}{3}\pi(2r)^2 \times 3h : \cfrac{1}{3}\pi(3r)^2 \times 2h\) \(= 12r^2h : 18r^2h\) \(= 2 : 3\)