Q.If the mean of a statistical distribution is 4.1, \(∑f_i x_i = 132 + 5k\), and \(∑f_i = 20\), then what is the value of \(k\)?

According to the question, \(\cfrac{132 + 5k}{20} = 8.1\) i.e., \(132 + 5k = 162\) i.e., \(5k = 162 - 132\) i.e., \(k = \cfrac{30}{5} = 6\) ∴ The required value of \(k = 6\) (Answer)
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